We Discuss About That NPTEL Cryptography And Network Security Assignment 7 Answer
NPTEL Cryptography And Network Security Assignment 7 Answer – Here All The Questions and Answers Provided to Help All The Students and NPTEL Candidate as a Reference Purpose, It is Mandetory to Submit Your Weekly Assignment By Your Own Understand Level.
Are you looking for the Assignment Answers to NPTEL Cryptography And Network Security Assignment 7 Answer? If Yes You are in Our Great Place to Getting Your Solution, This Post Should be help you with the Assignment answer to the National Programme on Technology Enhanced Learning (NPTEL) Course “NPTEL Cryptography And Network Security Assignment 7 Answer”
NPTEL Cryptography And Network Security Assignment
The aim of this course is to introduce the student to the areas of cryptography and cryptanalysis. This course develops a basic understanding of the algorithms used to protect users online and to understand some of the design choices behind these algorithms. Our aim is to develop a workable knowledge of the mathematics used in cryptology in this course. The course emphasizes to give a basic understanding of previous attacks on cryptosystems with the aim of preventing future attacks. A wide variety of basic cryptographic primitives will be discussed along with recent developments in some advanced topics like identity-based encryption, attribute-based encryption, functional encryption, two-party/multi-party computation, bitcoin and crypto-currency and postquantum cryptography. The cryptanalysis part will help us understanding challenges for cybersecurity that includes network security, data security, mobile security, cloud security and endpoint security.
This course can have Associate in Nursing unproctored programming communication conjointly excluding the Proctored communication, please check announcement section for date and time. The programming communication can have a weightage of twenty fifth towards the ultimate score.
- Assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
- ( All assignments in a particular week will be counted towards final scoring – quizzes and programming assignments).
- Unproctored programming exam score = 25% of the average scores obtained as part of Unproctored programming exam – out of 100
- Proctored Exam score =50% of the proctored certification exam score out of 100
UNPROCTORED PROGRAMMING EXAM SCORE >=10/25 AND PROCTORED EXAM SCORE >= 20/50.
CHECK HERE OTHERS NPTEL ASSIGNMENTS ANSWERS
BELOW YOU CAN GET YOUR NPTEL Cryptography And Network Security Assignment 7 Answer 2022? :
1. If r = 4(mod 17), r = 3(mod 11), then r =. (mod 187).
(a) 32
(b) 157
(c) 34
(d) 23
Answer:- b
2. Rabin cryptosystem is secure under the hardness of__________.
(a) decoding problem
(b) discrete logarithm problem
(c) factorization
(d) Subset-sum
Answer:- c
Cryptography And Network Security Assignment 7 Answers 2022
3.
Cryptography And Network Security Assignment 7 Answers 2022
Answer:- c
4. (11/51) +(7/11) =____________
(a) 1
(b) 0
(c)2
(d)-1
Answer:- b
5. All quadratic residues modulo 17 are_________________.
(a) 1,2,4, 8, 9, 13, 14, 16
(b) 1,2,4, 8,9, 11, 15, 16
(c) 1,2,3,8, 9, 13, 15, 16
(d) 1,2,4, 8,9, 13, 15, 16
Answer:- d
6. Let p, q are odd positive integers. Then, (p/q)= -(q/p)if
(a) p=q= 3(mod 4)
(b) p=q= 1(mod 4)
(C)p= q= 2(mod 4)
(d) none of these above
Answer:- a
Cryptography And Network Security Assignment 7 Answers 2022
7. Using Rabin cryptosystem with n = 161, encrypt message m = 24. The Ciphertext is ____________.
(a) 47
(b) 44
(c) 65
(d) 93
Answer:- d
8. Quadratic non-residues modulo 19 are ___________.
(a) 2,3,8, 10, 12, 13, 14, 17, 18
(b) 2,3,8, 11, 12, 13, 14, 15, 18
(c) 2,4,8, 10, 12, 13, 14, 15, 18
(d) 2,3,8, 10, 12, 13, 14, 15, 18
Answer:- d
9.
Cryptography And Network Security Assignment 7 Answers 2022
Answer:- c
10. Evaluate (4015/331).
(a). 0
(b). 2
(c). -1
(d). 1
Answer:- d
Yhaa You have done it but next? if YOU Want to your Others NPTEL Cryptography And Network Security Assignment 7 Answer Then Follow US HERE and Join Telegram.