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NPTEL Introduction to Operating Systems Assignment 3 Answer

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NPTEL Introduction to Operating Systems Assignment 3 Answer – Here All The Questions and Answers Provided to Help All The Students and NPTEL Candidate as a Reference Purpose, It is Mandetory to Submit Your Weekly Assignment By Your Own Understand Level.

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NPTEL Introduction to Operating Systems Assignment

ABOUT THE COURSE :
Operating systems (OS) provide the crucial interface between a computer’s hardware and the applications that run on it. It allows us to write programs without bothering much about the hardware. It also ensures that the computer’s resources such as its CPU, hard disk, and memory, are appropriately utilized. In this course, we dwell into how the OS manages to do all this in an efficient manner. This is an introductory course, for students with prior knowledge of computer organization. The course is based on an OS called xv6, which in many ways is similar to the Linux operating systems.

INTENDED AUDIENCE B.E./Msc (Computer Science)

PRE-REQUISITES Good knowledge of C, Computer Organization and Architecture, x86 Assembly level programming.

Next Week Assignment Answers

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This course can have Associate in Nursing unproctored programming communication conjointly excluding the Proctored communication, please check announcement section for date and time. The programming communication can have a weightage of twenty fifth towards the ultimate score.

Final score = Assignment score + Unproctored programming exam score + Proctored Exam score
  • Assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
  • ( All assignments in a particular week will be counted towards final scoring – quizzes and programming assignments). 
  • Unproctored programming exam score = 25% of the average scores obtained as part of Unproctored programming exam – out of 100
  • Proctored Exam score =50% of the proctored certification exam score out of 100
YOU WILL BE ELIGIBLE FOR A CERTIFICATE ONLY IF ASSIGNMENT SCORE >=10/25 AND
UNPROCTORED PROGRAMMING EXAM SCORE >=10/25 AND PROCTORED EXAM SCORE >= 20/50. 
If any one of the 3 criteria is not met, you will not be eligible for the certificate even if the Final score >= 40/100. 

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1 point
int main()
{
int i, n;
for(i = 1; i < n ; i++){
if (fork() == 0)
printf(“OS”);
}
printf(“NPTEL”);
}
Number of times OS and NPTEL printed ?
 
 
 
 
ans  – C
1 point
State True or False.

A program to compute the sum of first 5,000 numbers can be divided into 4 sub parts and executed on 4 CPUs using either fork or threads. The reason why we prefer fork is because large portions of the data/code between the 4 sub-parts are very similar and need not be duplicated.

 
 
ans  –  A
1 point
 Match the following:
1.NEW                    A. Waiting for an i/o
2.READY                B. Currently Executing
3.RUNNING            C. Process is being created
4.SLEEPING           D. waiting to be picked up by scheduler
 
 
 
 
ans  –  D
1 point
State True or False for a process currently in RUNNING state.
A software interrupt will result in the change to ring 1.
 
 
ans  –  B
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1 point
State True or False.
In the absence of system calls, a user process can never dynamically allocate memory.
 
 
ans  –  A
1 point
The wait() system call inside the parent process returns the pid of an exiting child process. Which of the following best fits when wait is called inside the child process?
 
 
 
 
ans  –  A
1 point
A student has written a program and used pid = fork() function call in it. The pid returned by the fork was 5129. Which of the following is true about the process invoking fork?
 
 
 
 
ans  –  C
1 point
State True/False

When the child process state is set to Zombie, all page directories and the kernel are also deallocated.

 
 
ans  –  B
1 point
Which of the below statement is False.
 
 
 
 
ans  –  D
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1 point
What is the output in the parent process?

int main()
{
int a=0, pid;
pid = fork();
if(pid == 0){
a= a – 10;
printf(“u = %d\n”,a);
}
else{
a= a + 10;
printf(“x = %d\n”,a);
}
}

 
 
 
 
ans  –  B
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