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NPTEL Introduction to Operating Systems Assignment 5 Answer

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NPTEL Introduction to Operating Systems Assignment 5 Answer – Here All The Questions and Answers Provided to Help All The Students and NPTEL Candidate as a Reference Purpose, It is Mandetory to Submit Your Weekly Assignment By Your Own Understand Level.

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NPTEL Introduction to Operating Systems Assignment

ABOUT THE COURSE :
Operating systems (OS) provide the crucial interface between a computer’s hardware and the applications that run on it. It allows us to write programs without bothering much about the hardware. It also ensures that the computer’s resources such as its CPU, hard disk, and memory, are appropriately utilized. In this course, we dwell into how the OS manages to do all this in an efficient manner. This is an introductory course, for students with prior knowledge of computer organization. The course is based on an OS called xv6, which in many ways is similar to the Linux operating systems.

INTENDED AUDIENCE B.E./Msc (Computer Science)

PRE-REQUISITES Good knowledge of C, Computer Organization and Architecture, x86 Assembly level programming.

Next Week Assignment Answers

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This course can have Associate in Nursing unproctored programming communication conjointly excluding the Proctored communication, please check announcement section for date and time. The programming communication can have a weightage of twenty fifth towards the ultimate score.

Final score = Assignment score + Unproctored programming exam score + Proctored Exam score
  • Assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
  • ( All assignments in a particular week will be counted towards final scoring – quizzes and programming assignments). 
  • Unproctored programming exam score = 25% of the average scores obtained as part of Unproctored programming exam – out of 100
  • Proctored Exam score =50% of the proctored certification exam score out of 100
YOU WILL BE ELIGIBLE FOR A CERTIFICATE ONLY IF ASSIGNMENT SCORE >=10/25 AND
UNPROCTORED PROGRAMMING EXAM SCORE >=10/25 AND PROCTORED EXAM SCORE >= 20/50. 
If any one of the 3 criteria is not met, you will not be eligible for the certificate even if the Final score >= 40/100. 

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1 point
The average turnaround time with the shortest remaining time first (SRTF) and shortest job first (SJF) scheduling for the seven processes listed
in the table is ___________
 
 
 
 
Ans –  C
1 point
Consider the context switching overhead of 1 unit. What is the context switching overhead while using SRTF and SJF scheduling for the
seven processes listed in the table above. Include the context switching to load the first process?
 
 
 
 
Ans –  B

For the processes listed in the table above, the schedule length is  _____________ with a FCFS scheduling scheme
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1 point
Consider 3 processes that start simultaneously. Each process from start to finish takes 40, 50, and 60  ms respectively. Of this, the first 20% of the time is spent waiting for IO events and the next 80% time for computation
1 point
The scheduler uses FCFS scheduling. Assuming that all I/O operations are overlapped. How much time in milli-seconds is the CPU idle?
 
 
 
 
Ans –  C
1 point
From the data given above, which of the following is the average turn around time considering only the time when a process is either running or in the ready queue?
 
 
 
 
Ans –  C

For the data given above, the schedule length is  _____________ assuming SRTF scheduling algorithm
1 point
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1 point
Shortest Remaining Time first algorithm is not practical
   Its time complexity is huge, which makes it unsuitable for real systems
   It requires knowledge of the burst time, which can be easily predicted
 
 
 
 

Ans –  B

Consider three process P1, P2, and P3 with arrival time (0, 1, 3) and burst time (6 ,5,4) respectively, what is the order of completion in SJF and RR scheduling with time slice of 2 units
1 point
Order of completion in SJF scheduling
 
 
 
 
Ans –  A
1 point
Order of Completion in RR scheduling
 
 
 
 
Ans –  D
1 point
Professor X suggests a method to alleviate starvation in scheduling algorithms. Under the new scheme, processes get a priority number.
The priority of the process is considered by the scheduling algorithm when scheduling. The new scheme will alleviate starvation
 
 
Ans –  A
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