NPTEL Real-Time Systems Assignment 5 Answers 2022
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NPTEL Real-Time Systems Assignment
ABOUT THE COURSE :
The rapid growth of applications deploying real-time technologies has been matched by the evolutionary growth of the underlying technologies supporting the development of real-time systems. In this course, some of the core technologies used in developing real-time systems will be discussed. Mainly, the software issues related to real-time systems will be discussed, keeping the hardware discussions to bare minimum. The software issues that will be addressed are quite expansive, including the operating system and program development issues, the networking and database issues, etc. Also, some of the popular commercial real-time operating systems and their important features will be discussed in this course.
Next Week Assignment Answers
This course can have Associate in Nursing unproctored programming communication conjointly excluding the Proctored communication, please check announcement section for date and time. The programming communication can have a weightage of twenty fifth towards the ultimate score.
- Assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
- ( All assignments in a particular week will be counted towards final scoring – quizzes and programming assignments).
- Unproctored programming exam score = 25% of the average scores obtained as part of Unproctored programming exam – out of 100
- Proctored Exam score =50% of the proctored certification exam score out of 100
UNPROCTORED PROGRAMMING EXAM SCORE >=10/25 AND PROCTORED EXAM SCORE >= 20/50.
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BELOW YOU CAN GET YOUR NPTEL Real-Time Systems Assignment 5 Answers 2022? :
Consider a set of three periodic real-time tasks that are to be run on a uniprocessor using a rate monotonic scheduler. The task characteristics are given in the following table. Assume that each context switch overhead is 1 milli second. What would be the worst case completion time for Task4?
Task Set (All times are in milliseconds)
Task Name
Phase
Execution time
Period
Deadline
Task1
10
10
100
100
Task2
150
15
150
150
Task3
100
10
40
40
Task4
50
25
200
200
a.137 milliseconds
b.145 milliseconds
c.173 milliseconds
d.215 milliseconds
e.231 milliseconds
Ans – A
Consider a set of four periodic real-time tasks that are to be run on a uniprocessor using a rate monotonic scheduler. The task characteristics are given in the following table. However, it was noted that Task2 is the most critical task. By applying the period transformation technique, what would be the execution time and period of Task2?
Task Set (All times are in milliseconds)
Task Name
Phase
Execution time
Period
Deadline
Task1
200
10
100
100
Task2
150
20
120
150
Task3
100
20
40
40
Task4
0
15
200
200
a.Execution time=10, Period=60
b.Execution time=10, Period=40
c.Execution time=8, Period=35
d.Execution time=5, Period=30
e.Execution time=5, Period=20
Ans – B
Which of the following are FALSE concerning a deferable server?(multiple options)
a.It serves a set of aperiodic tasks
b.It is an aperiodic task
c.It has much better response time for aperiodic tasks compared to polling server.
d.It preserves its execution time till the end of its period, if no aperiodic tasks are ready.
e.Its implementation is much more simpler than a polling server
Ans – C
Which of the following are FALSE concerning a priority exchange server?
a.It serves a set of aperiodic tasks
b.It is an aperiodic task
c.It has much better response time for aperiodic tasks compared to polling server.
d.It preserves its execution time till the end of its period, if no aperiodic tasks are ready.
e.It has much better response time for aperiodic tasks compared to deferable server.
f. When the priority exchange server is invoked by the scheduler, if no aperiodic tasks are ready, it exchanges its priority with a lower priority task that is ready.
g. Its implementation is simpler than a deferable server Consider a set of six periodic real-time tasks that are to be run on a uniprocessor-based embedded system using a rate monotonic scheduler. However, the embedded operating system supports only four priority levels? Which one of the following is the priority assignment using the uniform scheme? Assume pri(Ti) is the priority of Ti and priority level 1 is the highest priority and 4 is the lowest priority.
Ans – D
Task Set (All times are in milliseconds)
Task Name
Phase
Execution time
Period
Deadline
T1
200
10
100
100
T2
150
20
120
150
T3
100
20
40
40
T4
0
15
200
200
T5
50
35
300
300
T6
100
15
400
400
a.pri(T1)=1, pri(T2)=2, pri(T3)=3,pri(T4)=4,pri(T5)=4,pri(T6)=4
b.pri(T1)=2, pri(T2)=3, pri(T3)=1,pri(T4)=4,pri(T5)=3,pri(T6)=4
c.pri(T1)=3, pri(T2)=1, pri(T3)=2,pri(T4)=4,pri(T5)=4,pri(T6)=4
d.pri(T1)=2, pri(T2)=3, pri(T3)=1,pri(T4)=4,pri(T5)=4,pri(T6)=4
e.pri(T1)=3, pri(T2)=2, pri(T3)=1,pri(T4)=4,pri(T5)=1,pri(T6)=2 Which one of the following statement about the period transformation technique is true?
a.It is used for assign priority to some tasks with very long periods have very high criticality and to perform schedulability analysis in this situation
b.It is used for assign priority to some tasks with very short periods have very high criticality and to perform schedulability analysis in this situation
c.It essentially enables scheduling sporadic tasks by a rate monotonic scheduler by logically transforming those tasks into periodic tasks
d.It essentially enables scheduling aperiodic tasks by a rate monotonic scheduler by logically transforming those tasks into periodic tasks
Ans – C
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