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NPTEL Theory of Computation Assignment
ABOUT THE COURSE :
This is an introductory course on Theory of Computation intended for undergraduate students in computer science. In this course we will introduce various models of computation and study their power and limitations. We will also explore the properties of the corresponding language classes defined by these models and the relations between them. We will assume the student is comfortable in analytical reasoning and has preferably done a course on Data Structures and Algorithms.
PRE-REQUISITES: It is recommended that the candidate has done a course in Data Structures and Algorithms.
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Next Week Assignment Answers
This course can have Associate in Nursing unproctored programming communication conjointly excluding the Proctored communication, please check announcement section for date and time. The programming communication can have a weightage of twenty fifth towards the ultimate score.
Assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
( All assignments in a particular week will be counted towards final scoring – quizzes and programming assignments).
Unproctored programming exam score = 25% of the average scores obtained as part of Unproctored programming exam – out of 100
Proctored Exam score =50% of the proctored certification exam score out of 100
YOU WILL BE ELIGIBLE FOR A CERTIFICATE ONLY IF ASSIGNMENT SCORE >=10/25 AND UNPROCTORED PROGRAMMING EXAM SCORE >=10/25 AND PROCTORED EXAM SCORE >= 20/50.
If any one of the 3 criteria is not met, you will not be eligible for the certificate even if the Final score >= 40/100.
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2 points
If L1≤mL2 and L1 is decidable, then L2 is If L1≤mL2 and L1 is decidable, then L2 is
Undecidable Undecidable
Cannot be determinedCannot be determined
Turing recognisableTuring recognisable
Ans – C
2 points
Which of the following is not implied by P=NP? Mark all that apply. Which of the following is not implied by P=NP? Mark all that apply.
3-SAT can be solved in polynomial time3-SAT can be solved in polynomial time
Factoring can be solved in polynomial timeFactoring can be solved in polynomial time
Halting problem can be solved in polynomial timeHalting problem can be solved in polynomial time
Graph Isomorphism can be solved in polynomial time.Graph Isomorphism can be solved in polynomial time.
Ans – B,C,D
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2 points
Which of the following languages are undecidable?Which of the following languages are undecidable?
A={⟨M⟩∣M is a TM and L(M) is not a finite language}A={⟨M⟩∣M is a TM and L(M) is not a finite language}
B={⟨M⟩∣M is a TM and 11111100110∈L(M)}B={⟨M⟩∣M is a TM and 11111100110∈L(M)}
C={⟨M⟩∣M is a TM and all strings are in L(M)}C={⟨M⟩∣M is a TM and all strings are in L(M)}
None of these languagesNone of these languages
Ans – A,C,D
5 points
For languages A and B, let A≤mB. Which of the following statements is (are) true? For languages A and B, let A≤mB. Which of the following statements is (are) true?
If B is regular, then A is regular.If B is regular, then A is regular.
If B is CFL, then A is CFL. If B is CFL, then A is CFL.
If B is Turing recognizable, then A is Turing recognizable If B is Turing recognizable, then A is Turing recognizable
If B is decidable, then A is decidable.If B is decidable, then A is decidable.
Ans – C,D
2 points
Let A be a Turing recognizable language. If A≤mA¯ then what can we say about A?Let A be a Turing recognizable language. If A≤mA¯ then what can we say about A?
A is decidable.A is decidable.
A is undecidable. A is undecidable.
A¯ is Turing recognizable. A¯ is Turing recognizable.
A is regular.A is regular.
Ans -A,C
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5 points
For a positive integer n, the number L(n) is defined as the maximum number of steps that an n-stateTuring machine can make on a initially blank tape before halting.Consider a function f such that L(n)≤f(n) for all n. The function f is For a positive integer n, the number L(n) is defined as the maximum number of steps that an n-stateTuring machine can make on a initially blank tape before halting.Consider a function f such that L(n)≤f(n) for all n. The function f is
Computable in polynomial timeComputable in polynomial time
Computable in exponential timeComputable in exponential time
Computable in non-deterministic polynomial timeComputable in non-deterministic polynomial time
UncomputableUncomputable
Ans – B
2 points
The statement NP¯¯¯¯¯¯¯¯=coNP is The statement NP¯=coNP is
TrueTrue
FalseFalse
Ans – A
5 points
Which of the following statements is true?Which of the following statements is true?
P≠NP⟹NP≠coNPP≠NP⟹NP≠coNP
NP≠coNP⟹P≠NPNP≠coNP⟹P≠NP
NP⊆coNP⟹NP=coNPNP⊆coNP⟹NP=coNP
NP⊆coNP⟹NP≠coNP
Ans – All
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