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Split The String CodeChef Solution

We Are Discuss About CODECHEF SOLUTION

Split The String CodeChef Solution

Split The String CodeChef Solution

For a binary string¬†A, let¬†f(A)¬†denote its¬†badness, defined to be the difference between the number of zeros and number of ones present in it. That is, if the string has¬†c_0¬†zeros and¬†c_1¬†ones, its badness is¬†|c_0 – c_1|. For example, the badness of “01” is¬†|1 – 1| = 0, the badness of “100” is¬†|2 – 1| = 1, the badness of “1101” is¬†|1 – 3| = 2, and the badness of the empty string is¬†|0 – 0| = 0.

You are given an integer N and a binary string S.

You would like to partition S into K disjoint subsequences (some of which may be empty), such that the maximum badness among all these K subsequences is minimized. Find this value.

Formally,

  • Let¬†S_1, S_2, \ldots, S_K¬†be a partition of¬†S¬†into disjoint subsequences. Every character of¬†S¬†must appear in one of the¬†S_i. Some of the¬†S_i¬†may be empty.
  • Then, find the¬†minimum¬†value of¬†\max(f(S_1), f(S_2), \ldots, f(S_K))¬†across all possible choices of¬†S_1, S_2, \ldots, S_K¬†satisfying the first condition.

Input Format

  • The first line of input will contain a single integer¬†T, denoting the number of test cases.
  • The description of each test case is as follows:
    • The first line contains two space-separated integers¬†N¬†and¬†K.
    • The second line contains¬†the binary string¬†S¬†of length¬†N.

Output Format

‚ÄčFor each test case,¬†print the minimum possible value of the maximum badness when¬†S¬†is partitioned into¬†K¬†subsequences.

Constraints

  • 1 \leq T \leq 1000
  • 1 \leq N \leq 2 \cdot 10^5
  • 1 \leq K \leq 10^9
  • S¬†is a binary string, i.e, contains only the characters¬†0¬†and¬†1
  • The sum of¬†N¬†across all test cases doesn’t exceed¬†2 \cdot 10^5

Sample 1:

Input

Output

3
7 5
1010100
4 1
1100
6 2
101111
1
0
2

Explanation:

Test case¬†1:¬†Let’s take a couple of examples.

  • Suppose the partition is¬†\{“10”, “10”, “0”, “10”, “\ “\}, obtained as¬†\textcolor{red}{10}\textcolor{blue}{10}\textcolor{orange}{10}0¬†(elements of one color form a subsequence). The respective badness values are¬†\{0, 0, 1, 0, 0\}, the maximum of which is¬†1.
  • Suppose the partition is¬†\{“101”, “00”, “\ “, “10”, “\ “\}, obtained as¬†\textcolor{red}{10}10\textcolor{red}{1}\textcolor{blue}{00}. The respective badness values are¬†\{1, 2, 0, 0, 0\}, the maximum of which is¬†2.

The first partition, with a maximum badness of 1, is one of the optimal partitions.

Test case¬†2:¬†The only possible partition is¬†\{“1100″\}, which has a badness of¬†0.

Test case¬†3:¬†The partitions¬†\{“1011”, “11”\}¬†and¬†\{“0111”, “11”\}¬†both lead to a badness of¬†\max(2, 0) = 2, which is the minimum possible.

SOLUTION

Split The String CodeChef Solution

SOLUTION

Split The String CodeChef Solution

SOLUTION

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